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feat: implement binary number literals

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TopchetoEU 2024-12-27 19:15:20 +02:00
parent 8a34db833c
commit c971fde0e2
Signed by: topchetoeu
GPG Key ID: 6531B8583E5F6ED4
1 changed files with 31 additions and 0 deletions
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31
src/main/java/me/topchetoeu/jscript/common/parsing/Parsing.java
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@ -206,6 +206,27 @@ public class Parsing {
return ParseRes.res(res, n);
}
private static ParseRes<Double> parseBin(Source src, int i) {
int n = 0;
double res = 0;
while (true) {
int digit = src.at(i + n, '\0') - '0';
if (digit < 0 || digit > 9) break;
if (digit > 1) return ParseRes.error(src.loc(i + n), "Digits in binary literals must be from 0 to 1, encountered " + digit);
if (digit < 0) {
if (n <= 0) return ParseRes.failed();
else return ParseRes.res(res, n);
}
n++;
res *= 2;
res += digit;
}
return ParseRes.res(res, n);
}
public static ParseRes<String> parseString(Source src, int i) {
var n = skipEmpty(src, i);
@ -267,6 +288,16 @@ public class Parsing {
if (negative) return ParseRes.res(-res.result, n);
else return ParseRes.res(res.result, n);
}
else if (src.is(i + n, "0b") || src.is(i + n, "0B")) {
n += 2;
var res = parseBin(src, i + n);
if (!res.isSuccess()) return res.chainError(src.loc(i + n), "Incomplete binary literal");
n += res.n;
if (negative) return ParseRes.res(-res.result, n);
else return ParseRes.res(res.result, n);
}
else if (src.is(i + n, '0')) {
n++;
parsedAny = true;